Quoted from Inkochnito:The specs for the LT1083 do look good.
The resistors match.
Does anyone have any idea about the heat dissipation with the original heat sink?
Does the LT1083 match the pinout?
I'd have to check. Being these are both linear regulators, efficiency will suck regardless, but I can look at the numbers as a sanity check.
So being linear, whatever the input voltage is, minus the output voltage (x the current) is what will be dissipated. For example. 12V in, 5V out= 7 V across the part. Power is V * I. 7V (across the regulator) and let's use 5A: 7V * 5A = 35 watts as heat. That's a given regardless of the part.
However, the parts are different and there's a chance that one could be better at getting the heat out of the part vs. the other. That's due to the thermal resistance of the part (which ultimately determines the die temperature). i.e. The die being the 'part' (no case) - it has to remain below a certain temp. See below.
Sorry, got a little technical there.
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